To complete this exercise, you must master three core programming concepts:
// After finishing a row, toggle the starting color for the next row // Since we toggled an odd number of times (8 toggles), // the boolean is already opposite of row start. // But careful: after even number of columns, toggling 8 times // brings us back to original state. So we must toggle once more // to alternate row starting color. if (COLS % 2 == 0) isBlack = !isBlack;
Note: Depending on the exact CodeHS instructions for V2, you might be working with a Grid class or a 2D array of Strings/Objects rather than primitive integers. The algorithmic logic ( (row + col) % 2 == 0 ), however, remains exactly the same. Common Pitfalls and How to Fix Them 9.1.7 Checkerboard V2 Codehs
Remember that the outer loop handles rows ( array[row] ) and the inner loop targets columns ( array[row][col] ). Swapping these will crash your program if the grid is not perfectly square.
: A common expert strategy is to check if the sum of the current row index and column index is even or odd. (row + col) % 2 == 0 , set the value to 1. Otherwise, keep it as 0. Assignment Requirement autograder often strictly requires you to use an assignment statement board[i][j] = 1 ) rather than just printing the pattern directly. Step-by-Step Implementation Review Initialize the Board To complete this exercise, you must master three
If COLS were odd, this extra toggle wouldn’t be necessary, but here it is.
This skill directly translates to drawing game boards (chess, checkers, tic-tac-toe), data visualizations, and tile-based maps. if (COLS % 2 == 0) isBlack =
Alternatively, the same logic can be written in a slightly different but functionally identical way:
If you want, I can:
: Use the provided print_board function to output your final 8x8 nested list in a readable format. Common Pitfalls